So, If I had a graphing calculator Im pretty sure I could figure it out, but with keno:

So normal Keno is an 80 number board where you pick up to 10 numbers (we’ll just state the max for the sake of the example) and then 20 numbers are drawn at random…

On stake though the board is halved to 40, you still pick 10 numbers, but only 10 numbers are drawn…

So my question is, how much worse are the odds of (will pick 6 and 7 for reference [higher end hits] ) hitting the same amount of numbers on Stake?

To the layman (without an understanding of factorials and probability); it seems either like the “same odds”, or “even better” as you have 10/40 rather than 10/80 numbers and the “boards halved so the called numbers being halved makes sense”. But it doesn’t work like that an I know some of you math people on here probably can do it easier than I can (really don’t want to pencil out 80x79x78x77…/80x79x78x77…- 20x19x18x17…. Etc.)Thanks in advanced if you answer the question; greatly appreciate it 🙏