Getting Wolfram Alpha to return only the smallest positive integer from a set

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Given any real numbers a & b, I can have Wolfram Alpha solve for x where a*x = floor(a*x) && b*x = floor(b*x).

For some (a,b) pairs the result will be the set of all integer multiples of some particular non-zero integer. For example, given a = 1.25 and b = .75, Wolfram responds that x = 4n for all integers n ∈ Z.

How can I tell Wolfram Alpha that I only want x = the smallest positive integer that satisfies the stated conditions?

Thanks!

edit: min(1.25x = floor(1.25x) && .75x = floor(.75x)), x> 0

returns x = 4n, n ∈ Z, n >= 1

but is there a way to have the result simply be x = 4?

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Posted: 2 years ago
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