Hello! I have a question about how recursion works.

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(define (unzip plist)

(if(null? plist)

'(().())

(cons (cons (caar plist) (car (unzip (cdr plist))))

(cons (cdar plist) (cdr (unzip (cdr plist)))))))

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So basically, this code combines the first digit of each pair to the next one, so for example,

(unzip (list (cons 1 4) (cons 2 5) (cons 3 6)))

this would result in ( 1 2 3 (4 5 6))

So my question is, how exactly does the recursion works, so it takes the caar of plist, which would be 1, and then for (car (unzip (cdr plist))), from what I understand, it recurses the program but this time with ((cons 2 5) (cons 3 6)), but if this is the case, wouldnt it be (caar (unzip (cdr plist)))? since the car of ((cons 2 5) (cons 3 6)) is (2 5) while the caar is 2? Thank you and sorry if its a dumb question. Please let me know if my question isn't clear! I don't think I'll ever able to wrap my head around all of this :(