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20 mL of 0.0496 mol Lā€“1 CH3NH2 (a weak base) was placed into a conical flask. A titration was carried out using 0.0553 mol Lā€“1 of a solution of a monoprotic acid.

The equation for the reaction is shown with the monoprotic acid represented as HA.

CH3NH2(aq) HA(aq) CH3NH3 (aq) Aā€“(aq

pKa(CH3NH3 ) = 10.64

(i) Calculate the initial pH of the solution of CH3NH2 before any acid is added.

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