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A motorcyclist who is moving along an x axis directed toward the east has an acceleration given by a = (6.60 - 1.20t) m/s2 for 0 ≤ t ≤ 6.0 s. At t = 0, the velocity and position of the cyclist are 2.80 m/s and 7.3 m.
(a) What is the maximum speed achieved by the cyclist?
(b) What total distance does the cyclist travel between t = 0 and 6.0 s?
This is what I have so far:http://www.imgur.com/eBkLk.jpeg
a(t) = (6.6 - 1.2)t
v(t) = ∫a(t)dt = 6.6t - .6t2 C; v(0) = 2.8
v(t) = 6.6t - .6t2 2.8
x(t) = ∫v(t)dt = -.2t3 3.3(t2) 2.6t C; but x(0) =7.3 so
x(t) = -.2t3 3.3t2 2.6t 7.3
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