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Maclaurin polynomial Calculus2
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I need help doing this problem http://imgur.com/KXSDq1
I can do the derivatives.
f(x)=e3x
f'(x) = 3e3x
f''(x) = 9e3x
f'''(x) = 27e3x
f4(x) = 81e3x
Maclaurin formula
( fn(x) (x-c)n ) / (n!)
; where c = 0
So going up to n=4 (starting with n=0 I assume)
f(x) (x)/(0!)
f'(x) (x) / (1!)
f''(x) (x) / (2!)
f'''(x) (x) / (3!)
f4 (x) (x) / (4!)
and substitute:
e3x (x) / 1
3e3x (x) / (1)
9 e3x (x) / (2)
27e3x (x) / (6)
81e3x (x) / (24)
I'm assuming all this is correct, how do I do the second part?
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