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Consider a 9 digits number divisible by 9 and when its last digit is removed ...the resulting 8 digit number should divisible , then 7 digit divisible by 7 and so on..Find the 9 digit number.
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def findno(num):if len(str(num)) == 1:return True;
return num%len(str(num)) == 0 and findno(num//10)
for i in range(10000000,99999999):if findno(i):print(i)
correct this..
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- 11 months ago
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