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[Question] Why is permutations of a string n(n!) time complexity?
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vanmoonshine is in Question
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When coding for permutations it appears there is an outer for loop and an inner for loop that runs recursively with n-1 string length and a prefix. So my question is why is it n(n!) opposed to just n!? Since the recursive call starts with n-1 shouldn't it run n! because when it bubbles up to the highest level it'll result in the last calls being (n * n-1) opposed to (nnn-1)? Any clarification on this would be amazing.

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7 years ago