Psychrometry question (FE Mech)

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I'm having trouble with nailing down exactly how enthalpy works in Psychrometry.

In the 10.3 FE Handbook pg. 150, the enthalpy equation is:

h = ha w*hv

So if I were to calculate rate of heat transfer as a change in enthalpy I would assume the equation would be something like:

q = (h2a - h1a) (w2 - w1)*hv

The issue is that the problems I'm doing sometimes flip the sign like so:

q = (h2 - h1) - (w2 - w1)*hf3

I'm very uncomfortable just memorizing an equation unless I can derive and understand it, and it seems to directly conflict what's in the current handbook. Is there something I'm missing? Thanks.

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Dr_Manatee

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